DoElect

Most industrial types of equipment are inductive loads hence, they required two kinds of power been consumed by them ( kW - to perform the actual work and kVAR - reactive power to sustain the magnetic field of the load ). Example of inductive load - Electric motors, Induction furnaces, Lighting ballasts, etc basically loads with the composition of coils for their design. While kW is the useful power required to keep the machine running. The kVAR basically does not perform any useful work except to help to sustain the magnetic field in the equipment. For example - if you had an electric motor that was operating at 100kW and the apparent power was 125kVA. Hence, power factor will be 0.8 (kW/kVA = 100/125 = 0.8pf). This means kVA decreases if pf increases. As an example - A 100kW load operating at 142kVA will have 0.7pf (70% efficient) and at 105kVA the pf will be 0.95(95%). This means the more you correct your pf the lesser the kVA that will be consumed and the lesser the utility you ar

 Most loads in modern electrical distribution network are inductive and resistive loads.  Resistive loads are loads that convert all form of energy to heat and they always have heating element incorporated in there design. Examples include: Incandescent bulb, heater, cooker etc. Resistive Load: Resistive loads require one type of current - - Working power (kW) which is used to perform the actual work of creating heat, light etc Inductive Load: Inductive loads are loads that operate base on the principle of electromagnetic induction. They always have coils in them.  Example includes: Transformers, electric motor, fan etc. When a current is supplied to an inductive load. It converts this current to magnetic using the coil inside it. Because it is an inductive load, current lags voltage by an angle of 90 degree. Inductive load requires two kinds of current: - Working power (kW) to perform useful and actual work of creating heat, motion, machine output etc - Reactive power (kVAR) to sustai